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OpenStudy (31356):
I got (x+4)(x+4)
Correct?
OpenStudy (31356):
@jim_thompson5910
@melissaholmes
OpenStudy (anonymous):
hi!
OpenStudy (anonymous):
No, sorry. (x+4)(x-1)
OpenStudy (31356):
Can you show me how you get it?
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OpenStudy (anonymous):
sure
OpenStudy (31356):
Hi @MelissaHolmes ! :D
How was your Valentine's Day?
OpenStudy (anonymous):
4-1 has to equal 3, and 4*-1 has to equal -4
OpenStudy (31356):
Okay
OpenStudy (anonymous):
valentine's day was ok... didn't do much...
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jimthompson5910 (jim_thompson5910):
To factor x^2+3x-4, you need to find two numbers that
a) multiply to -4 (last term)
AND
b) add to 3 (middle coefficient)
OpenStudy (31356):
So Fullerene was correct?
jimthompson5910 (jim_thompson5910):
These two numbers are 4 and -1
4*(-1) = -4
4 + (-1) = 3
That means x^2+3x-4 factors to (x+4)(x-1)
The order of the factors does not matter. So we can also say (x-1)(x+4)
OpenStudy (31356):
Okay thanks!
OpenStudy (anonymous):
good job @Fullerene and @jim_thompson5910 :D
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OpenStudy (31356):
They sure did! :D
OpenStudy (anonymous):
Thanks!
OpenStudy (31356):
Can you help me with another one?
OpenStudy (31356):
x^2+8x+16
jimthompson5910 (jim_thompson5910):
find two numbers that
a) multiply to 16 (last term)
AND
b) add to 8 (middle coefficient)
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OpenStudy (31356):
I got (x+4)(x+4)
Is that correct?
jimthompson5910 (jim_thompson5910):
Good, x^2+8x+16 factors to (x+4)(x+4)
You can write that as (x+4)^2
OpenStudy (31356):
Okay thanks!
jimthompson5910 (jim_thompson5910):
np
OpenStudy (31356):
Can you help me with several more? thanks in advance.
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OpenStudy (31356):
x^2-7x-8
OpenStudy (anonymous):
yeah
OpenStudy (31356):
I got (x-1)(x+8)
Is it correct?
OpenStudy (anonymous):
(x - 8)(x + 1) actually
OpenStudy (31356):
Is it @jim_thompson5910 ?
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jimthompson5910 (jim_thompson5910):
MelissaHolmes is correct
notice how -8 + 1 = -7
OpenStudy (31356):
Oh okay, thanks again!
OpenStudy (anonymous):
yay! i got it right! :D
OpenStudy (31356):
Good job! :D
jimthompson5910 (jim_thompson5910):
whereas, your answer expands out to x^2 + 7x - 8 since -1 + 8 = 7
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OpenStudy (31356):
Thanks!
OpenStudy (31356):
x^2-10x+25?
OpenStudy (31356):
I got (x-5)(x-5)
OpenStudy (anonymous):
yeah... i think thats right :D
OpenStudy (31356):
Is it @jim_thompson5910 ?
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jimthompson5910 (jim_thompson5910):
yep or \(\Large (x-5)^2\) works too
OpenStudy (31356):
Thanks again, both of you!
OpenStudy (31356):
x^2+4x+4?
OpenStudy (31356):
I got (x+2)(x+2)
jimthompson5910 (jim_thompson5910):
good
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OpenStudy (31356):
Thanks!
OpenStudy (31356):
x^2-4x-12
Is it (x-2)(x+6)?
OpenStudy (anonymous):
(x - 6)(x + 2)... i think
OpenStudy (31356):
@jim_thompson5910
@MelissaHolmes
OpenStudy (31356):
Okay thanks!
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OpenStudy (anonymous):
:D good job @31356! :)
OpenStudy (31356):
Thanks!
OpenStudy (anonymous):
anytime! :D
OpenStudy (31356):
x^2+10x+25
Is it (x+5)(x+5)
OpenStudy (31356):
@MelissaHolmes
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OpenStudy (anonymous):
yup! :D
OpenStudy (31356):
Yea!
OpenStudy (anonymous):
:D
OpenStudy (31356):
x^2-8x+16
Is it (x-4)(x-4)
OpenStudy (anonymous):
yup again :D
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OpenStudy (31356):
Yea!
OpenStudy (31356):
x^2-4x-12?
Is it (x-2)(x+6)?
OpenStudy (anonymous):
(x - 6)(x + 2) actually..... close, though. XD
OpenStudy (31356):
Oh okay, thanks!
OpenStudy (anonymous):
yw :D
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OpenStudy (31356):
No more questions left! :D
OpenStudy (anonymous):
Ok! :D :)
OpenStudy (31356):
:D
OpenStudy (31356):
x^2+4x-12
Sorry, need help, forgot this question. lol
@MelissaHolmes
OpenStudy (anonymous):
ok!
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OpenStudy (anonymous):
so what did u get?
OpenStudy (31356):
:D, thanks for always helping me! :)
OpenStudy (31356):
I am stuck on this one.
OpenStudy (anonymous):
ya, you're my friend... friends help each other out...
OpenStudy (31356):
Yes, indeed, my friend, lol
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OpenStudy (anonymous):
and ok... i see what u mean... give me a sec to figure this one out...
OpenStudy (31356):
Ok
OpenStudy (anonymous):
does this thing have answer choices?
OpenStudy (31356):
No
OpenStudy (31356):
:(
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OpenStudy (anonymous):
hmmm...
OpenStudy (anonymous):
OH!!!!
(x + 6)(x - 2)
OpenStudy (31356):
Yea! Thanks!
OpenStudy (31356):
:D
OpenStudy (anonymous):
you are very welcome! :D
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