Question

tan110-tan80/1+tan110*tan50=??tan2.2°

tan60°

tan160°

tan550°

Answer 1

tan2.2°

Answer 2

can u find the same pattern in ur question too ?

Answer 3

\[\tan ( a- b ) = \frac{ \tan \ a - \tan b }{ 1 + \tan \ a \ \tan \ b }\]

Answer 4

yes i have the same pattern!

Answer 5

\[\tan ( 110 - 50 ) = \frac{ \tan 110 - \tan 50 }{ 1 + \tan 110 \tan50}\]

Answer 6

so... u can find ur answer now :)

Answer 7

then would it be tan60? (:

Answer 8

yep:)

Answer 9

Thank you !!

Answer 10

u r welcome!

Answer 11

@***[ISURU]*** .. u are answering..! :p