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Two fair dice are thrown. What is the probability of getting a total of 5 or 10? (1,4)(2,3)(4,6)(5,5) (4/36)*2=2/9? @Callisto
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this is an long explanation... The sum of two dice: 1 2 3 4 5 6 +------------------- 1 | 2 3 4 5 6 7 2 | 3 4 5 6 7 8 3 | 4 5 6 7 8 9 4 | 5 6 7 8 9 10 5 | 6 7 8 9 10 11 6 | 7 8 9 10 11 12 so the probability of getting 5 or 10 is = the required probability / total nu. of events = 7/36
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