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Calculus1
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$ \displaystyle{ \int { \ln {x} \over x^5 } \,dx } $
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\[\int\limits \frac{ x }{ x ^{5} }dx=\int\limits x ^{-4}dx=?\]
\[\int\frac{\ln x}{x^5}~dx\] Integrate by parts: \[\begin{matrix}u=\ln x&&&dv=x^{-5}~dx\\ du=\frac{1}{x}~dx&&&v=-\frac{1}{4}x^{-4}\end{matrix}\] \[\int\frac{\ln x}{x^5}~dx=-\frac{1}{4}x^{-4}\ln x+\frac{1}{4}\int\frac{1}{x^5}~dx\]
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