Question

please help!!!Solve sec^2θ + tanθ - 3 = 0 for 0° ≤ θ < 90°.

θ = ???

Answer 1

Replace sec^2 with 1 + tan^2

Answer 2

\[1+\tan ^2\theta + \tan \theta -3=0\]
\[\tan ^2\theta +\tan \theta -2=0\]

Answer 3

Factor and set each factor equal to 0

Answer 4

would it beθ = 45 perhaps??

Answer 5

I would think there would be more than 1 answer. Did you factor?

Answer 6

ttop: Try factoring x^2 + x - 2 = 0 as an example of how to approach this problem.
Then do the same thing to tan2θ+tanθ−2=0.