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Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5.. A) −93 B) −33 C) 33 D) 93
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There is a shortcut way, but since you only have 5 to do, it isn't hard:
n(1) = 3(-2)^(1-1); n(1) = 3 n(2) = 3(-2)^(2-1); n(2) = -6 n(3) = 3(-2)^(3-1); n(3) = 12 n(4)= 3(-2)^(4-1); n(4) = -24 n(5) = 3(-2)^(5-1); n(5) = 48 3-6+12-24+48 = 33
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