Question

Find a cubic function with the given zeros.

Square root of six., - Square root of six., -3

f(x) = x3 - 3x2 - 6x - 18

f(x) = x3 + 3x2 - 6x - 18

f(x) = x3 + 3x2 + 6x - 18

f(x) = x3 + 3x2 - 6x + 18

Answer 1

(x +6)(x-6)(x+3) = 0

Answer 2

i have x^3+3x^2-36-108=0

Answer 3

you have to multiply each term
someone else was also responding. i guess he changed his mind
i will do it now

Answer 4

you forgot your x
then factor the 6

Answer 5

x^3 + 3x^2-36x-108

Answer 6

\[(x-\sqrt{6})(x+\sqrt{6})(x+3)=0\] I think you can expand from here.

Answer 7

how did you get it?

Answer 8

sorry i made a mistake it should be as above rt 6

Answer 9

(x-rt6)(x +rt6)(x+3)
recognise the difference of 2 squares?
(x^2-6)(x+3)
expaND
X^3-6X+3X^2-18
Rearrange to put in order of degree
x^3 +3x^2 -6x-18

Answer 10

sorry recognize