Question

Explain how to find tangent & normal for this question: y=x ^{2}-3 (2,1)

Answer 1

whats the equation for y ?
to find slope of tangent you'll need
dy/dx
can you find it ?

Answer 2

normal line is perpendicular to the tangent an in the xy plane in this case

Answer 3

is \(y = x^2-3\)
??
dy/dx =... ?