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Physics 21 Online
OpenStudy (anonymous):

A 2.5 Coulomb charge is placed in an electric field where it experiences an electrical force of 50.N. What is the value of the electrical field at the place where the charge is located? Show all work

OpenStudy (anonymous):

F=Eq 50=E*2.5 20N/C=E

OpenStudy (anonymous):

thank you!

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