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Rewrite with only sin x and cos x. cos 3x
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\[\cos 3x=\cos \left( 2x+x \right)=?\] cos(a+b)=cos a cos b-sin a sin b
sin 2a =2sin a cos a
I'm sorry, I'm lost
you want to write formula for cos 3x or you want to derive the formula.
The question asks to rewrite cos 3x
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\[\cos 3x=4\cos ^{3}x-3\cos x\] if you want to derive this formula then proceed as written above.
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