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Find all complex solutions of 3x^2+x+4=0 I have -4 did I do this right?
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a = 3 b = 1 c = 4 x= -1 +- sqrt(1 - 4*3*4) / (2*3) x = -1 +- sqrt (-47) / 6 x1 = (-1/6) + i* (6.8556546004 / 6) x2 = (-1/6) - i*(6.8556546004 /6)
So, both solutions are complex and so you weren't right with an answer of -4
Thank you!
And here's a calculator to see if you have done the work correctly: http://www.1728.org/quadratc.htm
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