Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

nothing

OpenStudy (anonymous):

@eliassaab @beccaboo333

OpenStudy (cybershadow):

just rearrange the equation 2x^2+3x+5=0 now its solution wud be \[x=-b+\sqrt{b^2-4ac}/2a , x = -b-\sqrt{b^2-4ac}/2a\]

OpenStudy (cybershadow):

where a ,b are coefficients of x^2 , x and c is the constant term, got any doubts ?ask em

OpenStudy (anonymous):

I'm still confused :(

OpenStudy (cybershadow):

what part?

OpenStudy (anonymous):

math is my worst subject and I hate invisible numbers

OpenStudy (anonymous):

I don't get how to solve.

OpenStudy (cybershadow):

just put a = 2 , b = 3 and c = 5 in the equation i gave to u, dat will be ur answer

OpenStudy (anonymous):

\[x = -3 \pm i \sqrt{31} / 4\] ?

OpenStudy (cybershadow):

Yep thats the answer

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!