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@eliassaab @beccaboo333
just rearrange the equation 2x^2+3x+5=0 now its solution wud be \[x=-b+\sqrt{b^2-4ac}/2a , x = -b-\sqrt{b^2-4ac}/2a\]
where a ,b are coefficients of x^2 , x and c is the constant term, got any doubts ?ask em
I'm still confused :(
what part?
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math is my worst subject and I hate invisible numbers
I don't get how to solve.
just put a = 2 , b = 3 and c = 5 in the equation i gave to u, dat will be ur answer
\[x = -3 \pm i \sqrt{31} / 4\] ?
Yep thats the answer
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