Question

What is the solution of the linear-quadratic system of equations?
{y = x^2 + 5x - 3
{y - x = 2

Answer 1

Use substitution.
We know that:
\(y = x+2\)
Plug it in:
\(x+2 = x^2+5x-3\)

Do you know what to do from there?

Answer 2

no

Answer 3

\[x^2+4x-5 = 0\]
\[(x-1)(x+5) = 0\]
x = -5 or 1

Now you know \(x\) so solve for \(y\).

Answer 4

Oh ok I see, one second

Answer 5

So:
y = -2 or 3
right?

Answer 6

Yes, you are correct :-).