Question

x^4-5x^3+7x^2-3x=o

I know the zeroes are supposed to by x=1, x=3, and x=1. I just don't know how to solve the equation.

Answer 1

hmmm how do you know "x=1, x=3, and x=1" ?

Answer 2

I put the equation into a quartic equation solver online. It gave me the answer but didn't show how it got it.

Answer 3

heeh

Answer 4

well.... do you know how to do long division of polynomials?

Answer 5

factor out x and then use synthetic division.

Answer 6

\[x(x^3-5x^2+7x-3)=0\]