Question

Calculus II FTC

Answer 1

i cant do number c)

Answer 2

That's by the main definition of FTC. you take the antiderivate and evaluate at the endpoints.

Answer 3

\(\large \mathbb{g(1) -g(-1) = \int_0^1f(t^2)2tdt - \int_0^{-1}f(t^2)2tdt}\)

\(\large \mathbb{~~~~~~~~~~~~~~~~ = \int_0^1f(t^2)2tdt + \int_{-1}^{0}f(t^2)2tdt}\)

\(\large \mathbb{~~~~~~~~~~~~~~~~ = \int_{-1}^{0}f(t^2)2tdt} + \int_0^1f(t^2)2tdt \)

\(\large \mathbb{~~~~~~~~~~~~~~~~ = \int_{-1}^{1}f(t^2)2tdt} \)