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OpenStudy (anonymous):
Find the maximum or minimum of the following quadratic function: y =x2 - 10x + 25
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OpenStudy (jellisoncollege):
set y to zero 0=x^2-10x+25 0=(x-5)(x-5) 0=x-5 (move 5 to the other side) x=5 Maximum and minimum is 5.
OpenStudy (anonymous):
thanks !
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