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Find the unit tangent vector T(t) at the point with the given value of the parameter t. r(t) = cos ti + 8tj + 3 sin 2tk, t = 0
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what is r'(0) ?
10?
is it < 8/10 , 6/10 > ??
no, this R^3, what you got is R^2
well isn't it 4/5 j +3/5 k ???:S
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r(t) = <cost, 8t, sin(2t)> r'(t) = <-sint, 8, 2cos(2t) >
so, r'(0) = <0, 8, 2>
equation for a line r(t) = t<0,8,2> + r(0)
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