Question

-3x^2 + 52x + 378 = 0 ... slove ths by completing the square method.

Answer 1

start by factoring out the GCF

Answer 2

??? opss sry, it must be sloved with spilitting the middle term , ......

Answer 3

yes, thats the second step

Answer 4

first step for all these methods is to factor out GCF if any..

Answer 5

however there is no GCF here :)
so lets continue wid splitting the middle term..

Answer 6

before doing that, just make sure u dont have any typo in the middle term
is it really 52, and not 42 ? ??

Answer 7

let me check , a sec plz

Answer 8

okie

Answer 9

yeah! i got 52 only, .... actually question is , a vehicle travels at a certain average speed for a distance of 63km and thn travels a ditance of 72km at an average speed of 6km/h more than its original speed. if it takes 3 hours to complete the total journey, what si its original averge speed???

Answer 10

ths is the actually question, after slovign i got tht above question answer, .......

Answer 11

one sec..

Answer 12

hehe maybe i sloved it wrong, ... coudl u plz slove it

Answer 13

sure...

Answer 14

\(\large \mathbb{

\frac{63}{x} + \frac{72}{x+6} = 3


}\)

Answer 15

is that the equation u got ?

Answer 16

yeah! yes i got tht 1 only, .....

Answer 17

okay lets simplify this and solve :)

Answer 18

sure ...

Answer 19

\(\large \mathbb{

\frac{63}{x} + \frac{72}{x+6} = 3

}\)


\(\large \mathbb{


\frac{63(x+6)}{x(x+6)} + \frac{72x}{x(x+6)} = 3


}\)

\(\large \mathbb{


63(x+6)+ 72x = 3x(x+6)


}\)

Answer 20

fine ?

Answer 21

a sec let me check, ....... had anet probelm just now

Answer 22

accha!!! so we must multiply x(x+6) to 3 also,!!! didn't knew :P

Answer 23

yes !

Answer 24

yeah! wt after tht???

Answer 25

\(\large \mathbb{

\frac{63}{x} + \frac{72}{x+6} = 3

}\)


\(\large \mathbb{


\frac{63(x+6)}{x(x+6)} + \frac{72x}{x(x+6)} = 3


}\)

\(\large \mathbb{


63(x+6)+ 72x = 3x(x+6)


}\)

\(\large \mathbb{


21(x+6)+ 24x = x(x+6)


}\)


\(\large \mathbb{


21x+126+ 24x = x^2+6x


}\)


\(\large \mathbb{


x^2-39x -126 = 0


}\)

Answer 26

you wud get that quadratic...
usko sovle kar

Answer 27

if u want, u may split the mid term :
-126 = -42*3
-39 = -42+3

Answer 28

\(\large \mathbb{


x^2-39x -126 = 0


}\)



\(\large \mathbb{


(x+3)(x-42) = 0


}\)

Answer 29

\(\large \mathbb{


x=-3~~~ x = 42


}\)

Answer 30

discard the negative value
so the original average speed during the first 63km is \(42\)

Answer 31

\(42 \) kmph

Answer 32

see if that makes some sense

Answer 33

oopsss a doubt , .... after tht >>> 21(x+6)24x= x (x+6)
21x+126+24x= x^2 +6x...
thr above hw did u / y did u add 24x again?

Answer 34

anyways thnks

Answer 35

hey u still have that doubt ?

Answer 36

yeah! :( , poor in maths

Answer 37

no you're very good, and thats a good question to ask actually..
let me give it to u bit detailed

Answer 38

\(\large \mathbb{


63(x+6)+ 72x = 3x(x+6)


}\)

divide both sides by 3 :

wat do u get ?

Answer 39

omg!!! sm1 prasied me tht alos in maths , ....... let me slove wait, ....
21(x+6) + 24x = x(x+6) , ...

Answer 40

huraay! i got it , ..... by myself

Answer 41

yes thats right ! you're smart lol

Answer 42

:P smart , heheh applying butter on me, ... anyways wt abt ths question>

Answer 43

wat question ha

Answer 44

u already solved it by urself
u got 24x right -_-

Answer 45

PT and QT are two tangents to the circle, if angle PTQ = 50 degree, find angle PSQ and angle OPQ. ....

Answer 46

oh another question ok go ahead..

Answer 47

another quetion men, ....... tht question is already slove :P

Answer 48

ok ok just realized lol :D

Answer 49

draw it out

Answer 50

:P , ... hw to slove tht 1

Answer 51

start by drawing the circle and tangents
and also label them

Answer 52

sec plz