Question

Find y''(x) by implicit differentiation from sqrt(x)+sqrt(y)=1

Answer 1

\[
\frac{y'(x)}{2
\sqrt{y(x)}}+\frac{1}{2
\sqrt{x}}=0\\
y'(x)=-\frac{\sqrt{y(x)}}{\sqrt{x}}

\]

Answer 2

Can you find y''(x)?

Answer 3

i can get for y'....but i stuck when to find y''....