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what is the value of x in the equation √3 +x-5 = -2
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\[\sqrt 3+x-5 = -2 \rightarrow \sqrt 3+x = 5-2 \rightarrow \sqrt 3+x = 3\] \[\rightarrow x = 3 -\sqrt 3 = 3- 1.732 =1.268\] @Buchanan
my choices are a 3 b 46 c 6 d 12
Pls check your question again and then post
Is your question written like \[\sqrt{3+x} -5=-2\]
radical 3 +5 -5 = -2
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yes
Ok
\[\sqrt{3+x} -5=-2 \rightarrow \sqrt{3+x} =5-2 \rightarrow \sqrt{3+x} =3\] Squaring both sides we find \[( \sqrt{3+x})^2 =(3)^2 \rightarrow 3+x = 9 \rightarrow x= 9-3 \rightarrow x= 6\] Hence x=6 is the required answer. @Buchanan
thank you
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