Question

how do i find the indefinite integral of tan^3(x)sec^2(x)dx?

Answer 1

try \(u=\tan(x)\)
should get it in one step

Answer 2

what do you mean?

Answer 3

\[u=\tan(x), du =\sec^2(x)dx\]
\[\int \tan^3(x)\sec^2(x)dx=\int u^3du\] etc

Answer 4

oh okay i see it thank you so much,:)

Answer 5

yw