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Find an equation of the line containing the point (-1,3) and perpendicular to the line x+2y=-6.
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What is the slope of the line x+2y =6?
\[ x+ 2 y =6\\ 2 y = -x + 6\\ y= -\frac 12 x +3 \]
The answer to my first question is -1/2
(-1,3) The slope of the perpendicular line is 2. \[ y-3 = 2 (x+1)\\ y= 2 x +2 +3\\ y= 2x +5 \]
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