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Solve 2x2 - 8x = -7.
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4 - 8x = -7 -8x = -7 - 4 -8x = -11 8x = 11 x = 11/8 x = 1 3/8 or 1.375
these are my choices
1. Add 7 to both sides. 2. Plug into the quadratic formula 3. a = 2, b = -8, c = 7
Is the 2x squared (see below) or does it say 2 times 2?\[2x ^{2}\]
its 2x squared (:
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ahhhhh... 2x^2, very different! LOL hold on
hahah alright (:
@olivia0311 What did you get when you plugged into the formula?
\[x=8\pm \sqrt{8} \over 4 \]
Yes. \[\frac{8\pm \sqrt{8}}{4}\]
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So divide out the 4
And simplify radical 8
\[-2\pm 2 \sqrt{2}\]
?
@Mertsj
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\[\frac{8\pm \sqrt{8}}{4}=\frac{8\pm2\sqrt{2}}{4}=\frac{4\pm \sqrt{2}}{2}=2\pm\frac{\sqrt{2}}{2}\]
oh okay, I see what I did wrong, thank you so much
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