A rectangular yard is surronded by a fence that is 4 feet longer than it is wide. if the perimeter of the fence is 424 feet what are the dimensions of the yard it encloses?

Question

anonymous · Answer

P=2L+2W for rectangles.
The fence is 4 feet longer than it is wide. This translates into L=W+4.
Substitute this L value along with your perimeter value and solve.

P=2L+2W
424=2(W+4)+2W
424=2W+8+2W
424=4W+8
416=4W
***104=W***

We know that L=W+4, so let's plug in our new W value.
L=W+4
L=104+4
***L=108***

The yard is 108 ft by 104 ft.

anonymous · Answer

thanks!!! can you help with few more?