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If the measurement of a central angle is 5 pi over 6, find the length of its intercepted arc in a circle with a radius of 15 inches.
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use \[S = r \ \theta\] where S =intercepted arc length r= radius \[\theta = \angle \] can u do that ?
in your problem \[\theta = \frac{ 5 \pi }{ 6 }\] r= 15 inches plug them in to the equation
so s would equal 39.2?
yep!
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