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Find the equation of a line with the given points. (Put your answers in the form y = mx + b.) (6, 2) (5, 5)
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first find the slope.. can u find it ? \[slope = \frac{ y_{2} - y_{1} }{ x_{2} -x_{1} }\]
then u can use point slope form... since u know the coordinates..
\[slope = \frac{ 5-2 }{ 5-6 }\] \[slope =-3\]
now the standered form of a function is y = mx + b where m = slope b = intercept... now since u know the slope y= -3x + b to find be u can use (6 , 2) if u plug them in to ur equation 6 =-3(2) + b b = 12 so... the equation is y = -3x + 12 got it :) ?
thank you
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