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find all values of x in the interval [0,2pi] that satisfy the equation. 10cos(x)-5=0
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solve for cos(x) and it should be apparent.
if you know the unit circle, that is.
10cosx-5=0 ---> 5(2cos x -1)=0 5=0 ; 2cos x -1 = 0 ---> cos x = 1/2 ----> x = cos^-1(1/2), which is pi/3. Right?
is that the only one in the interval?
along with 4pi/3. Correct?
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not that one
5pi/3
there you go! great job!
thanks. I was rather unsure
trust yourself and check to be sure.
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