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Solve -3e^(x+1)-21= -27
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e^(x+1)=2
x+1=ln2
x=ln2-1
x=-0.3
(x+4)(x-2)=7
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x^2+2x-15
=0
(x+5)(x-3)=0
x=-5 or 3
thank you. ln(5x-3)-lnx= ln2
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5x-3=2x
x=1
\[\log_{3}(x-24)+\log_{3}x= 4 \]
x(x-24)=81
x^2-24x-81=0
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x^2-27x+3x-81=0
x(x-27)+3(x-27)=0
(x+3)(x-27)=0
x=-3 or 27
log(x+4)=log(x-2)+1
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(x+4)/(x-2)= 10
x+4=10x-20
x=24/9=8/3
Al wants to invest $50,000. His options are either to invest his money into an account paying 1.75% a.p.r. compounded quarterly for 3 years or he can put his money into an account paying 1.7% a.p.r. compounded continuously for 3 years. Which option should he choose? How much extra money would reproduced in the more profitable account?
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