Question

choose the correct simplification of (4x^3-3x-7)-(3x^3+5x+3)

Answer 1

a.) 7x^3-2x-4
b.)x^3-8x-10

Answer 2

First distribute to get

(4x^3-3x-7)-(3x^3+5x+3)

4x^3-3x-7-3x^3-5x-3

now combine like terms

Answer 3

c.) 7x^3+2x-4
d.)x^3+8x+10

Answer 4

Combine like terms.

Let's change the - to a + first.

(4x^3-3x-7)+(-3x^3-5x-3)

Now, this is simply addition. Let's group the like terms.

(4x^3-3x^3)+(-3x-5x)+(-7-3)

And combine.

x^3-8x-10. Choice B.

Answer 5

(4x^3-3x-7)-(3x^3+5x+3) should actually be (4x^3-3x-7) + (3x^3+5x+3)

Answer 6

(4x^3-3x-7) + (3x^3+5x+3)

4x^3-3x-7 + 3x^3+5x+3

now combine like terms

Answer 7

I got 9x^6+10 I know its wrong though :/

Answer 8

4x^3 and 3x^3 are like terms

this is because they both have the same variable term x^3

Answer 9

to combine like terms, you just add the numbers in front of the variable terms

these are the coefficients, which are 4 and 3

4+3 = 7

Answer 10

so

4x^3 + 3x^3 = 7x^3

Answer 11

do the same with other like terms

Answer 12

okay I think the answer is a

Answer 13

which is what?

Answer 14

7x^3-2x-4

Answer 15

-3x + 5x = ???

Answer 16

oooo wait its actual 7x^3+2-4

Answer 17

better, it's 7x^3 + 2x - 4

Answer 18

thanks :) can you help me with another?

Answer 19

sure I can do one more

Answer 20

two groups of campers, group a and group b hiked two different routes from their campsite to a waterfall. group a hiked through vista point to reach the waterfall. group b hiked directly to the waterfall the figure shows the distance they hiked:

which simplified expression can be used to find the difference in miles hiked by the two groups?
a.)2x-1
b.)2x+1
c.)2x+3
d.)2x+7

Answer 21

how far did group a hike?

Answer 22

Total distance for group A would be (x-1) + (2x+5) or 3x + 4. Total distance for group B would just be x + 3. I think the answer is b?

Answer 23

group A traveled more, so you'll find the difference like so

(group A) - (group B)

(3x + 4) - (x + 3)

3x + 4 - x - 3

2x + 1

so you are correct

Answer 24

yay!!! :) thanks I really appreciate your help

Answer 25

you're welcome