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Solve for x, given the equation Square root of x minus 5 + 7 = 11.
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\[\sqrt{x-5}+7=11\] subtract \(7\) to get \[\sqrt{x-5}=4\] then square to get \[x-5=16\]
is it extraneous?
it is x−5−−−−−√+7=11 subtract 7 to get x−5−−−−−√=4 then square to get x−5=16
what grade are you in veronicafresta
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