Ask your own question, for FREE!
Algebra 7 Online
OpenStudy (anonymous):

Factor by grouping: 5n^3-10n^2+3n-6

OpenStudy (whpalmer4):

\[5n^3-10n^2+3n-6\]To factor by grouping, first we must group :-) \[(5n^3-10n^2) + (3n-6)\]Now factor each group: \[5n^2(n-2)+3(n-2)\]Do you see a common factor in those two product terms?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!