Question

The length of a rectangle is 10 more than twice its width. The area is 72square inches. Find the dimensions of the rectangle

Answer 1

area= length x width
let x be the width
area= (10x)(x)
\(72=10x^2\)
and solve for 'x'
that will be the width
substitute the value of 'x' in length=10x

Answer 2

Thank you Data_lg2

Answer 3

But can you explain why it's not 2w-10=72^2in

Answer 4

np :)
and
\(\Large \color{blue}{Welcome\ to\ OPENSTUDY!! ☺☺☺}\)




hmm.. my bad, i did not read the question properly
"length of a rectangle is 10 more than twice its width"
so lemme do it again
let x-width
\(\Large 10+2x = 72\)
^this should be the equation, sorry:/

you almost got it, but instead of "-", it should be "+" because it says there that it is "10 more than" (^_^)

Answer 5

Thank you again
And fixing your mistake

Answer 6

hehehe, sorry :/