Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shrutipande9):
if\[\frac{ a }{ b}=\frac{ c }{ d}\]
then prove that \[\frac{ a }{ b }=\sqrt{a^{2}+c^{2}}/ \sqrt{b^{2}+d^{2}}\]
OpenStudy (shrutipande9):
nirmal help kar meri sis ko plzz....
OpenStudy (nirmalnema):
nahi ban raha =P sorry
OpenStudy (shrutipande9):
@hartnn ?
OpenStudy (shrutipande9):
@divu.mkr ...help right now
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (nirmalnema):
waise ye kis topic ka que hai.??
OpenStudy (shrutipande9):
ratio and proportion
OpenStudy (anonymous):
cbse me literally bohot chota topic h :P
just substitution karna h....ratios ko..
OpenStudy (shrutipande9):
bhai full bata...
OpenStudy (anonymous):
num me sqrt ke andar c^2 se multiply divide
aur denom me d^2 se
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (nirmalnema):
usse kya hoga...
OpenStudy (nirmalnema):
shayad kuch aya...
a/b = c/ d
\[a^2/b^2 = c^2/d^2\]
\[a^2/b^2= (a^2+c^2)/(b^2+d^2)=a^2*(b^2+d^2)/b^2*(a^2+c^2)\]
aise hi
\[c^2/d^2=(a^2+c^2)(b^2+d^2)\]
ye bhi upar wale jaisa hi aye ga..
to dono ko equate kar de ge to a/b=c/d..
aa jaye ga shayad//
OpenStudy (shrutipande9):
thank u nirmal...:D thoda modify karna pada..but got d ans..thank u..:D
OpenStudy (nirmalnema):
are gajab ye to sahi nikla...mai to majak majak mei kuch bhi kare ja raha tha..... =P