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Mathematics 14 Online
OpenStudy (shrutipande9):

proportion question

OpenStudy (shrutipande9):

if\[\frac{ a }{ b}=\frac{ c }{ d}\] then prove that \[\frac{ a }{ b }=\sqrt{a^{2}+c^{2}}/ \sqrt{b^{2}+d^{2}}\]

OpenStudy (shrutipande9):

nirmal help kar meri sis ko plzz....

OpenStudy (nirmalnema):

nahi ban raha =P sorry

OpenStudy (shrutipande9):

@hartnn ?

OpenStudy (shrutipande9):

@divu.mkr ...help right now

OpenStudy (nirmalnema):

waise ye kis topic ka que hai.??

OpenStudy (shrutipande9):

ratio and proportion

OpenStudy (anonymous):

cbse me literally bohot chota topic h :P just substitution karna h....ratios ko..

OpenStudy (shrutipande9):

bhai full bata...

OpenStudy (anonymous):

num me sqrt ke andar c^2 se multiply divide aur denom me d^2 se

OpenStudy (nirmalnema):

usse kya hoga...

OpenStudy (nirmalnema):

shayad kuch aya... a/b = c/ d \[a^2/b^2 = c^2/d^2\] \[a^2/b^2= (a^2+c^2)/(b^2+d^2)=a^2*(b^2+d^2)/b^2*(a^2+c^2)\] aise hi \[c^2/d^2=(a^2+c^2)(b^2+d^2)\] ye bhi upar wale jaisa hi aye ga.. to dono ko equate kar de ge to a/b=c/d.. aa jaye ga shayad//

OpenStudy (shrutipande9):

thank u nirmal...:D thoda modify karna pada..but got d ans..thank u..:D

OpenStudy (nirmalnema):

are gajab ye to sahi nikla...mai to majak majak mei kuch bhi kare ja raha tha..... =P

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