Help! just double checking to see if i am right. What is the P(Red l Heart) when drawing one card?
Perv^ Since a Heart is a red card the numerator can be simply written as P(Red | Heart) = P(Heart) / P(Heart) = [13/52] / 13/52 = 13/52 * 52 / 13 = 1
there is 13 red hearts in a card deck and there is 52 cards all together thats how I got 13 and 52
gtbishawt this is a place for homework not a place for getting a girl friend ps she is smooking hot i just hope i see her in real life i will mess her up after we have sex we will have it agian non stop bam she will be sucking my wingspan in front of your face
Eew... and thanks! Cpt.Sparz!!:) Can you hlep with something else?
sure
It's all good they got no life xD
what girl you know you want mee
.... you are disgusting creatures...
:D thanks! What is the P(Jack ∩ Club) when drawing one card?
ya you know i am i cant wait to see ya
No problem ! P(Jack | Face Card) = P( Jack and Face Card) / P(Face Card) A Jack is a face card so the numerator of the above fraction can be written simply as P(Jack | Face Card) = P(Jack) / P(Face Card) P(Jack) = 4/52 P(Face Card) = 12/52 So P(Jack | Face Card) = (4/52) / (12 / 52) = 4/52 * 52/12 = 4/12 P(Jack | Face Card) = 1/3
Makes so much more sense! lol Thank you so much! lol mind if i ask you two more things??
sup goergus
na ask away
lol no problem and sure :D
dude she was talking to mee
lol alright mate
dude what grade is you in
:D yay! thanks - Cpt.Sparz! Choose an employed person at random. Let A be the event that the person is female and B be the event that the person holds a managerial position. Data from the U.S. Department of Labor suggests that P(S) = 0.47 and P(BlA) = 0.34. a) Explain what P(A) = 0.47 means in context b) Explain what P(BlA) = 0.34 means in context
I'm a junior XD
To be honest idk this one... I:
This will take sometime, but sometimes i get these right.
How much time can i get to try to solve this?
Nice Asking Alexandria shirt btw! :D only junior i know with good taste in music.
lol that's fine. i appreciate the attempt in helping though:)
As long as you need! FlvsGirl
Yea, this question is like not working out with me
haha its fine.. i appreciate the attempt though :)
ok? what else do you need?
lol Ty gtb
No problem! :D
still trying to figure out the problem sorry it's taking so long
@Cpt.Sparz Same here >.<
lol yea it's kind of hard
Haha, yea my brain is dead on this one.....Sorry to the one who asked it, I tried but I cant come to a right answer and explaination :/
Yea same it's irritating when I can't help at all
@Cpt.Sparz So true, hey are you able to acceptp messages? We can collaberate on this problem, if not cool
That's completely fine you guys. :) Don't beat yourselves up over it, i just appreciate your attempt at helping!:)
yea I can accept messages
@gtb0329 Thanks....Yea, im puzzled.....
@Cpt.Sparz Cool, yea I am like really troubled with the problem. :/
lol yeah, its definitely a frustrating problem
Yea same here
@gtb0329 I fanned you, and thanks for being cool over it all....
haha thanks! XD and it's no problem at all.. just glad you've tried :)
Math isnt my strongest subject......though I push myself to learn it and know it
Yea math i'm good at but not the best
I'm really good, but only if i am taught properly
Dont worry, I will not rest till I get it....Never Shout Never..... I love the guy/group Never Shout Never
nice lol.. they remind me of the rocket summer
I think I did it, I dont know P(Red | Heart) = P(Red card and Heart) / P(Heart) Since a Heart is a red card the numerator can be simply written as P(Red | Heart) = P(Heart) / P(Heart) = [13/52] / 13/52 = 13/52 * 52 / 13 = 1 P(Red | Heart) = 1 This makes sense, since if you knew you that the card you picked was a heart (which is a red card) you would be absolutely certain that you picked a red card.
It took me 4everrrrrr, but I had to keep fixxing it
i meant romance on a rocketship, but they work too.. and yeah, Cpt.Sparz already gave me that :P But it is right!:D
@Cpt.Sparz How did i do? I think I did okay, but not great
Same thing really lol good job :D
Thank you, lol....My brain can not rest, though not for long for I have to do spanish, and science
hahaha no problem I can help you in spanish if you like
haha yeah, i got a little feeling of Déjà vu with that... Ugh, i was so glad to get out of that class last year! it frustrated me so much. I can attempt to help you since i've already finished :D
@Cpt.Sparz Thanks sooo much...where though? I dont think there is a section for it
There is lol I've taken spanish 1 and 2...
yeah, i quit after that, i was not in the mood for a spanish 3
Meet me in the Spanish section, I will go type the questions...Spanish 1, sadly.
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