Question

What is the logarithmic form of the equation e^2x= 1732?

Answer 1

\(\large{ \bf log_{\color{red}{ a}}{\color{blue}{ b}}=y\implies {\color{red}{ a}}^y={\color{blue}{ b}}\\ \quad \\
{\color{red}{ 3}}^{2x}= {\color{blue}{ 1732}}}\)

Answer 2

what do you think?

Answer 3

log2x1732 = e

Answer 4

?