Question

y= 2/5x-3 in standard form

Answer 1

First multiply both sides by 5 to clear out the fraction

y= 2/5x-3

5y= 5*(2/5x-3)

5y = 2x - 15

Answer 2

Then you need to get the equation into Ax + By = C form, so you subtract 2x from both sides

5y = 2x - 15

5y-2x = -15

-2x + 5y = -15

and finally, multiply both sides by -1 to make the x coefficient positive

-2x + 5y = -15

-1(-2x + 5y) = -1*(-15)

2x - 5y = 15

Answer 3

thanks