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Mathematics 14 Online
OpenStudy (anonymous):

help with rational functions? http://prntscr.com/2u3457

OpenStudy (anonymous):

\[ \frac{x^3-1}{x^2-1}=\frac{(x-1 ) \left(x^2+x+1\right)}{(x-1) (x+1)}=\frac{x^2+x+1}{x+1} \]

OpenStudy (anonymous):

The function is continuous everywhere except at x=-1

OpenStudy (anonymous):

x=-1 is a vertical asymptote

OpenStudy (anonymous):

sorry i went afk but thanks @eliassaab :D

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