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\[ \frac{x^3-1}{x^2-1}=\frac{(x-1 ) \left(x^2+x+1\right)}{(x-1) (x+1)}=\frac{x^2+x+1}{x+1} \]
https://www.wolframalpha.com/input/?i=plot+%281+%2B+x+%2B+x^2%29%2F%28x+%2B+1%29
The function is continuous everywhere except at x=-1
x=-1 is a vertical asymptote
sorry i went afk but thanks @eliassaab :D
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