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Given right triangle ABC right angle at C, if A=5 and B=12 use pythagorean theorem to solve for C
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Pythagorean theorem is \(C=\sqrt{B^2+A^2}\)
A^2 + B^2 = C^2 5^2 + 12^2 = C^2 25 + 144 = C^2 169 = C^2 sq rt 169 = C 13 = C any questions ?
Thank you! and no that pretty much explained it.
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