Question

Find the distance between the points 2,-3 and 5,-4

Answer 1

d = sq rt (x2 - x1)^2 + (y2 - y1)^2
(2,-3) x1 = 2 and y1 = -3
(5,-4) x2 = 5 and y2 = -4
now we sub
d = sq rt (5 - 2)^2 + (-4 - (-3)^2
d = sq rt 3^2 + (-1^2)
d = sq rt (9 + 1)
d = sq rt 10
d = 3.16