Question

Help

Answer 1

Factor 49t^2 -9

Answer 2

http://www.wolframalpha.com/input/?i=factorize+49t%5e2+-9&incTime=true
hope this helps

Answer 3

\[a^{2}b^{2} - c^{2} = (ab - c)(ab+ c)\]

Answer 4

u can use this...
\[49t^{2} - 9 = 7^{2}t^{2} - 3^{2}\]

Answer 5

A.) (7t+3)(7t+3)
B.) (7t+3)(-7t-3)
C.) (7t+3)(7t-3)
D.) 7t-3

Answer 6

now it is in the same form of
\[a^{2}b^{2} - c^{2}\]
so.. use the same factorization ii used for the a^2b^2 - c^2

what will u get ?

Answer 7

ummmmm i have no clue i am horrible at factoring

Answer 8

\[a^{2}b^{2} - c^{2} = (ab - c)(ab +c)\]
\[7^{2}t^{2} - 3^{2} = ( \ \ \ ? \ \ )( \ \ ? \ \ )\]

Answer 9

they r almost identical ... can u do it now ?

Answer 10

just follow the pattern !

Answer 11

Would it be (7t-3)(7t+3)

Answer 12

yep!

Answer 13

yay!!! Thanks so much

Answer 14

u r welcome!

Answer 15

:D