Question

Help again please i will fan and medal

Answer 1

Factor by grouping

3n^3 - 12n^2 + 2n - 8

Answer 2

A.) (3n^2-2) (n+4)
B.) (3n^2+2) (n-4)
C.) (n+2) (3n-4)
D.) 3(n^3-4n^2)+2n-8

Answer 3

(3n2 + 2) • (n - 4)

Answer 4

B

Answer 5

THanks million

Answer 6

np