Question

2x2 + 10x + 12 = 0
Solve using the Quadratic formula

Answer 1

Do you know the Quadratic formula?

Answer 2

x=-b+-sqrtb^2-4ac/2(a) ?

Answer 3

when
\[ax^{2} + bx + c = 0\]
\[x = \frac{ - b \pm \sqrt{ b^{2} - 4ac } }{ 2a }\]

now in ur equation
a = 2
b= 10
c= 12

plug the in to the equation

can u do that ?

Answer 4

x=-10sqrt1?

Answer 5

\[x = \frac{ -10 \pm \sqrt{ 10^{2} - 4(24) } }{ 4 }\]

Answer 6

okay i got -10sqrt-1
what do i do now?

Answer 7

u will get
\[x = \frac{ -10 \pm \sqrt{4} }{ 4 }\]
which is
\[x = \frac{ -10 + 2 }{ 4 } \ \ or \ x= \frac{ -10 -2 }{ 4 }\]
so...
\[x = -2 \ \ \ \ \ or \ \ \ \ \ x= -3\]

Answer 8

got it :) ?

Answer 9

Yes THANKYOU!!!

Answer 10

u r welcome!