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Mathematics 21 Online
OpenStudy (anonymous):

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a blue marble, not replacing it, and picking a brown marble?

OpenStudy (anonymous):

green : 4/19 red : 2/19 yellow : 5/19 brown 1/19 blue: 7/19

OpenStudy (anonymous):

how do i do that? i have a TI-nspire cx and a TI -spire with 2 keyboards.

OpenStudy (anonymous):

i get confused because i understand the percentages but wouldn't it lessen because it says ''What is the probability of picking a blue marble, not replacing it, and picking a brown marble? '' and there are 7 blue so if you dont put them back it would be 12 so would it be \[\frac{ 7 }{12 } x \frac{ 1 }{ 12 }\] ?? the 1 counts for the brown

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