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negate the following statement: ∃x∀y [y > x → ∃z (z^2 + 5z = y)]
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∀x∃y [y < x → ∀z (z^2 + 5z ≠ y)] ? do I also change y < x to y > x?
I think so, but you also need to negate the "implies" (->).
what is the negation of →?
"p -> q" is the same as "NOT p OR q"
i think p→q=not p or q
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So you need to negate NOT p OR q, which should result in p AND NOT q.
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