Ask your own question, for FREE!
Trigonometry 17 Online
OpenStudy (anonymous):

2cos^2x+cosx=cos2x

OpenStudy (anonymous):

Wrong subject bro

OpenStudy (anonymous):

Nvm

OpenStudy (anonymous):

Da other guy in da wrong subject

OpenStudy (anonymous):

\[2\cos ^2x+\cos x=\cos 2x\] \[2\cos^2x+\cos x=\cos ^2x-\sin ^2x=\cos ^2x-(1-\cos ^2x)=2\cos ^2x-1,\cos x=-1\] \[\cos x=-1=\cos( \pi+2k \pi),x=(2k+1)\pi,where~k ~is~an~integer.\]

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!