3 2/9 times 6/7 as a mixed number in simplest form

Question

jdoe0001 · Answer

$\bf 3\cfrac{2}{9}\cdot \cfrac{6}{7}\implies \cfrac{3\cdot 9+2}{9}\cdot \cfrac{6}{7}\implies \cfrac{(3\cdot 9+2)\cdot 6}{9\cdot 7}$

anonymous · Answer

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jdoe0001 · Answer

ahemm you kinda bypassed PEMDAS
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                                        parentheses first

jdoe0001 · Answer

$\bf 3\cfrac{2}{9}\cdot \cfrac{6}{7}\implies \cfrac{3\cdot 9+2}{9}\cdot \cfrac{6}{7}\implies \cfrac{({\color{red}{ 3\cdot 9+2}})\cdot 6}{9\cdot 7}\implies \cfrac{{\color{red}{ 29}}\cdot 6}{63}$

anonymous · Answer

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