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If the first term is 10, the second is 1,000, the third is 100,000 and the fourth is 10,000,000. What is the 80th term.
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okay
1st term= 1 zero 2nd term= 3 zeros 3rd term= 5zeros . . .
nth term= a+(n-1)d zeros
where n=80 d=2 a=1 80th term= 1+(79)2 = 159 zeros
so the answer is 10^159
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