Question

Find the zeros of the polynomial function.

f(x) = x3 + 3x2 - x - 3

Answer 1

usual steps.... factorize it...

x^3 + 3x^2 - x - 3

= ( x - 1 ) ( x^2 + 4x +3 )

= ( x - 1) ( x^2 + x + 3x + 3 )

= ( x -1 )[ x( x+ 1) + 3(x + 1) ]

= ( x - 1) ( x + 3) (x + 1)

Answer 2

so... if u equal it to zero.. u will get
x = 1 or x = -3 or x = -1
which means the zeros are
1 , -3 , -1