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The diagonal of a square has a length of cm. Find the length of a side of the square.
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The diagonal of a square has a length of\[8\sqrt{2}\] cm. Find the length of a side of the square.
THE DIAGONAL OF A SQUARE=8√2 THUS YOU HAVE A RIGHT TRIANGLE WITH 2 EQUAL SIDES & A HYPOTENUSE OF 8 X^2+X^2=(8√2)^2 2x^2=64*2 x^2=64 x=64 cm
and this is the length
A. \[2\sqrt{2}\] B. 4cm C. \[5\sqrt{2}\] D. 8cm
@KhaakeNajaf
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divide by \(\sqrt2\) and get \(8\)
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