Question

if f(x) is a continuous function and f(2)=7 and f'(2)=-3, then f(2.01) is approximately

Answer 1

i guess they want you to linearize the function

Answer 2

\[y-y_1=m(x-x_1)\]
\[y-7=-3(x-2)\] or \(y=-3(x-2)+7\)
replace \(x\) by \(2.1\)

Answer 3

i.e.
\[y=-3(.1)+7\]